if a spring is compressed twice as much

However, we can't express 2^N different files in less than N bits. Describe an instance today in which you did work, by the scientific definition. Let's say that we compress it by x = 0.15 \ \mathrm m x = 0.15 m. Note that the initial length of the spring is not essential here. displacement, right? Two files can never compress to the same output, so you can't go down to one byte. a question mark here since I'm not sure if that is exactly right. Therefore, if we can take some files and compress them, we have to have some files that length under compression, to balance out the ones that shorten. Going past that you get diminishing returns. #-ve# sign indicates that restoring force acts opposite to the deformation of the spring. When you stand still on the bathroom scale the total force To subscribe to this RSS feed, copy and paste this URL into your RSS reader. I worked at an Amiga magazine that shipped with a disk. It starts when you begin to compress it, and gets worse as you compress it more. on the spring, so it has a displacement Calculate the elastic potential energy stored by the spring, assuming it is not stretched beyond. Is there a proper earth ground point in this switch box? However, the second and further compressions usually will only produce a file larger than the previous one. Concept check: any lossless data compression can be "defeated', right? Similarly if the pattern replacement methods converts long patterns to 3 char ones, reapplying it will have little effect, because the only remaining repeating patterns will be 3-length or shorter. So I'll call that the force Direct link to mand4796's post Would it have been okay t, Posted 3 years ago. Substitute these values to the spring potential energy formula: U = \frac {1} {2} k \Delta x^2 U = 21 kx2. D. A student is asked to predict whether the . This limit depends on its physical properties. why is work work area under the line? then you must include on every digital page view the following attribution: Use the information below to generate a citation. Decoding a file compressed with an obsolete language. This force is exerted by the spring on whatever is pulling its free end. Design an entire engine that can restore the information on the user side. The force resists the displacement and has a direction opposite to it, hence the minus sign: this concept is similar to the one we explained at the potential energy calculator: and is analogue to the [elastic potential energy]calc:424). The part the student got wrong was the proportionality between the compression distance and the energy in the system (and thus the distance the block slid). To log in and use all the features of Khan Academy, please enable JavaScript in your browser. So let's say if this is or what's being proposed, by the student is alright, if This means that a compression algorithm can only compress certain files, and it actually has to lengthen some. You do 30 J of work to load a toy dart gun. How high could it get on the Moon, where gravity is 1/6 Earths? Visit Stack Exchange Tour Start here for quick overview the site Help Center Detailed answers. Take run-length encoding (probably the simplest useful compression) as an example. Unfortunately, the force changes with a spring. Compressors like zip often try multiple algorithms and use the best one. To find the work required to stretch or compress an elastic spring, you'll need to use Hooke's Law. If the child pulls on the front wagon, the energy stored in the system increases. Did you know? store are probably spring scales. What is the kinetic energy of the fired dart? So, the normal number of times a compression algorithm can be profitably run is one. increase the force, just so that you offset the Direct link to rose watson's post why is the restorative fo, Posted 5 years ago. line is forming. On the surface of the earth weight and mass are proportional to each citation tool such as, Authors: Gregg Wolfe, Erika Gasper, John Stoke, Julie Kretchman, David Anderson, Nathan Czuba, Sudhi Oberoi, Liza Pujji, Irina Lyublinskaya, Douglas Ingram, Book title: College Physics for AP Courses. of compression. Because the height of the If the compression algorithm is good, most of the structure and redundancy have been squeezed out, and what's left looks pretty much like randomness. It is pretty funny, it's really just a reverse iterable counter with a level of obfuscation. much force I have to apply. Let's see how much No the student did not mention friction because it was already taken into account in question 3a. College Physics Answers is the best source for learning problem solving skills with expert solutions to the OpenStax College Physics and College Physics for AP Courses textbooks. X0 is a particular It's K. So the slope of this What are the differences between these systems? up to 2K, et cetera. One particular clock has three masses: 4.0 kg, 4.0 kg, and 6.0 kg. zero and then apply K force. Digital Rez Software is a leading software company specializing in developing reservation systems that have been sold worldwide. And that should make sense. rev2023.3.3.43278. objects attached to its ends is proportional to the spring's change Direct link to pumpkin.chicken's post if you stretch a spring w, Posted 9 years ago. Maybe I should compress to the If you weren't, it would move away from you as you tried to push on it. Compression (I'm thinking lossless) basically means expressing something more concisely. If the system is the water, what is the environment that is doing work on it? block leaves the spring, result in more energy when block leaves the spring, block leaves spring, which will result in the block going further, which will result, or the block going farther I should say, which will result in compressed and not accelerating in either A block of mass 0.3 kg and spring constant 24 N/m is on a frictionless surface. opposite to the change in x. 1.A spring has a natural length of 10 in. Direct link to Charles LaCour's post The force from a spring i, Welcome back. When disturbed, it If this object is at rest and the net force acting And so, not only will it go And here I have positive x going How high can it get above the lowest point of the swing without your doing any additional work, on Earth? How much? reduce them to a one-instruction infinite loop. A lot of the games I worked on used a small, fast LZ77 decompressor. Describe a system in which the main forces acting are parallel or antiparallel to the center of mass, and justify your answer. displacements. In physics, this simple description of elasticity (how things stretch) is known as Hooke's law for the person who discovered it, English scientist Robert Hooke (1635-1703). Y = (F/A)/(L/L), F/A = YL/L.Young's modulus is a property of the material. A child has two red wagons, with the rear one tied to the front by a stretchy rope (a spring). bit, we have to apply a little bit more force. Finally, relate this work to the potential energy stored in the spring. The line looks something To log in and use all the features of Khan Academy, please enable JavaScript in your browser. proportionally as a function of the distance, and [PREVIOUS EXAMPLE] Well, slope is rise A child has two red wagons, with the rear one tied to the front by a stretchy rope (a spring). Some algorithms results in a higher compression ratio, and using a poor algorithm followed by a good algorithm will often result in improvements. And why is that useful? compression. If you shoot a ping pong ball straight up out of this toy, how high will it go? start doing some problems with potential energy in springs, A crane is lifting construction materials from the ground to an elevation of 60 m. Over the first 10 m, the motor linearly increases the force it exerts from 0 to 10 kN. @dar7yl, you are right. How much energy does the clock use in a week? Is it possible to compress a compressed file by mixin and/or 'XOR'? Direct link to Ain Ul Hayat's post Let's say that the graph , Posted 6 years ago. over run, right? I was thinking about compression, and it seems like there would have to be some sort of limit to the compression that could be applied to it, otherwise it'd be a single byte. Basically, we would only have a rectangle graph if our force was constant! Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. energy once we get back to x equals zero. You can use Hooke's law calculator to find the spring constant, too. plot the force of compression with respect to x. There's a trade-off between the work it has to do and the time it takes to do it. stable equilibrium. Generally applying compression to a already compressed file makes it slightly bigger, because of various overheads. Practical compression algorithms work because we don't usually use random files. And the negative work eventually Now, let's read. sum of many kinds of energies in a system they are transformed with in. So when x is 0, which is right So, we're in part (b) i. Thus, the existence of there is endless scope to keep discovering new techniques to improve Possible Answers: Correct answer: Explanation: From the problem statement, we can calculate how much potential energy is initially stored in the spring. force we've applied. For example, you can't necessarily recover an image precisely from a JPEG file. I think you see a Whatever compression algorithm you use, there must always exists a file that does not get compressed at all, otherwise you could always compress repeatedly until you reach 1 byte, by your same argument. compressing the spring to the left, then the force I'm Suppose we have a file N bits long, and we want to compress it losslessly, so that we can recover the original file. If you compress a spring by X takes half the force of compressing it by 2X. of x to the left. In general for most algorithms, compressing more than once isn't useful. You want to know your weight. Twice as much Four times as much Question Image. as the x. more potential energy here because it takes more work to value for x. What information do you need to calculate the kinetic energy and potential energy of a spring? the distance, right? potential energy is gonna be converted to more kinetic A roller coaster is set up with a track in the form of a perfect cosine. and you understand that the force just increases doing is actually going to be the area under the A toy car is going around a loop-the-loop. This problem has been solved! energy is then going to be, we're definitely going to have equilibrium. The So this is really what you **-2 COMPRESSION, Further Compression Using Additonal Symbols as substitute values, 04.A.B.C VALUES Since there is no actual kick pedal with pad, it's just the same trigger as the hi hat pedal. Because the decompression algorithm had to be in every executable, it had to be small and simple. You can compress infinite times. since there are no repeating patterns. endstream endobj 1253 0 obj <>stream area A = 0.5 mm2. This is called run-length encoding. Staging Ground Beta 1 Recap, and Reviewers needed for Beta 2, Efficient compression of folder with same file copied multiple times. The force of compression Meaning now we have real compression power. Direct link to Ethan Dlugie's post You're analysis is a bit , Posted 10 years ago. However, when the displacements become large, the How much is the spring compressed when the block has a velocity of 0.19 m/s? per unit area F/A, called the stress, to the fractional change in length L/L. necessary to compress the spring by distance of x0. much into calculus now. How do you calculate the ideal gas law constant? It is a very good question. I've also seen it used in embedded systems where the decompresser had to be small and tight. You are launching a 0.315-kg potato out of a potato cannon. But the bottom line is the work If the block is set into motion when compressed 3.5 cm, what is the maximum velocity of the block? There's no obvious right answer. And what's the slope of this? (a) The ball is in stable equilibrium at the bottom of a bowl. much we compress, squared. Direct link to Will Boonyoungratanakool's post So, if the work done is e, Posted 5 years ago. How would you calculate the equation if you were putting force on the spring from both directions? be K times 1, so it's just going to be K. And realize, you didn't apply curve, each of these rectangles, right? How Intuit democratizes AI development across teams through reusability. first scenario, we compressed the block, we compressed the spring by D. And then, the spring ncdu: What's going on with this second size column? And then, the friction is acting against the motion of the block, so you can view it as it's Hydroelectricity is generated by storing water behind a dam, and then letting some of it run through generators in the dam to turn them. You want to Hope this helps! 4.4. OpenStax is part of Rice University, which is a 501(c)(3) nonprofit. the halting problem, which cannot exist, making the proof itself an How are zlib, gzip and zip related? the work done by us here is 4x2=8J. keep increasing the amount of force you apply. causes the block to stop. And, of course, work and on-- you could apply a very large force initially. Direct link to Paxton Hall's post Essentially, Sal was ackn, Posted 5 years ago. Adding another 0.1 N Before the elastic limit is reached, Young's modulus Y is the ratio of the force Express your answer numerically in meters to three significant figures. What was Sal's explanation for his response for b) i. ? Creative Commons Attribution License If you're seeing this message, it means we're having trouble loading external resources on our website. You have a cart track, two carts, several masses, a position-sensing pulley, and a piece of carpet (a rough surface) that will fit over the track. is the distance. A water tower stores not only water, but (at least part of) the energy to move the water. **-2 COMPRESSION. the spring in the scale pushes on you in the upward direction. student's reasoning, if any, are incorrect. of compression is going to be pretty much zero. But this is how much work is spring a little bit, it takes a little bit more force to What do they have in common and how are they different? One could write a program that can decompile into what it was, say a book, flawlessly, but could compress the pixel pattern and words into a better system of compression. Now we're told that in the first case it takes five joules of work to compress the spring and so we can substitute five joules for Pe one and four times that is going to be potential energy two which is 20 joules. To verify Hooke's Law, we must show that the spring force FS and the How many times can I compress a file before it becomes corrupt? This is because in stretching (or compressing),the exterenal force does work on the spring against the internal restoring force.This work done by the external force results in increased potential energy of the spring. How was the energy stored? (a)Find the force constant. Explain how you arrived at your answer. Direct link to akibshahjahan's post why is work work area und, Posted 6 months ago. so that's the force that the spring applies to whoever's Solution The correct option is B Two times The energy stored in the dart due to the compression of spring gets converted into kinetic energy. There's a special case though. you need to apply as a function of the displacement of Answer (1 of 4): In either case, the potential energy increases. Let's see what the questions are here. But in this situation, I pushed So my question is, how many times can I compress a file before: Are these two points the same or different? You are participating in the Iditarod, and your sled dogs are pulling you across a frozen lake with a force of 1200 N while a 300 N wind is blowing at you at 135 degrees from your direction of travel. But if you don't know Whenever a force is applied on a spring, tied at one end, either to stretch it or to compress it, a reaction force comes into play which tries to oppose the change. That's my y-axis, x-axis. Direct link to Eugene Choi's post 5: 29 what about velocity. its length changes by an amount x from its equilibrium If m is the mass of the dart, then 1 2kd2 = 1 2mv2 o (where vo is the velocity in first case and k is spring constant) 1 2k(2d)2 = 1 2mv2 (where v is the velocity in second case) 1 4= v2 o v2 v =2vo to be equal to the restorative force. endstream endobj 1254 0 obj <>stream The elastic limit of spring is its maximum stretch limit without suffering permanent damage. What is the net force, and will your kinetic energy increase or decrease? Describe and graph what happens to the kinetic energy of a cart as it goes through the first full period of the track. These notes are based on the Directorate General of Shipping Syllabus for the three month pre sea course for deck cadets Hooke's law is remarkably general. Old-fashioned pocket watches needed to be wound daily so they wouldnt run down and lose time, due to the friction in the internal components. Take run-length encoding (probably the simplest useful compression) as an example. So you have F=kx, say you had a 2m spring. Part two, here. a little r down here-- is equal to negative K, where K is on the spring and the spring exerts a force on the object. I'm not talking about any specific algorithm or particular file, just in general. Suppose a .74-kg mass on a spring that has been compressed 0.100 m has elastic potential energy of 1.20 J. Most of the files we use have some sort of structure or other properties, whether they're text or program executables or meaningful images. So the force is kind of that If wind is blowing horizontally toward a car with an angle of 30 degrees from the direction of travel, the kinetic energy will ____. Where does the point of diminishing returns appear? The applied force deforms the rubber band more than a spring, because when you stretch a spring you are not stretching the actual material of the spring, but only the coils. rectangle is the force I'm applying and the width is Let's draw a little Gravity acts on you in the downward direction, and But using the good algorithm in the first place is the proper thing to do. is acted on by a force pointing away from the equilibrium position. That means that eventually the file will start growing with each additional compression. It doesn't compress the string at each pass but it will with enough passes compress any digit string down to a zero length string. Zipping again results in an 18kb archive. displacement from equilibrium towards the equilibrium position, for very small on the object is zero, the object is at an equilibrium position. Would it have been okay to say in 3bii simply that the student did not take friction into consideration? 1.0 J 1.5 J 9.0 J 8.0 J 23. compress the spring that much is also how much potential distorted pushes or pulls with a restoring force proportional to the Knowing Hooke's law, we can write it down it the form of a formula: Where did the minus come from? 1500 N? Can data be added to a file for better compression? bit, how much force do I have to apply? Lets view to it as datastream of "bytes", "symbols", or "samples". DB Bridge So what I want to do here is now compressed twice as much, to delta x equals 2D. applying is also to the left. Since each pixel or written language is in black or write outline. If I'm moving the spring, if I'm When the ice cube is released, how far will it travel up the slope before reversing direction? I would like to state that the limit of compression itself hasn't really been adapted to tis fullest limit. How much are the springs compressed? In this case we could try one more compression: [3] 04 [-4] 43 fe 51 52 7 bytes (fe is your -2 seen as two's complement data). And actually, I'm gonna put If so, how close was it? And also, for real compressors, the header tacked on to the beginning of the file. Find the maximum distance the spring is . How many objects do you need information about for each of these cases? on you is zero. This required a large number of turns of the winding key, but not much force per turn, and it was possible to overwind and break the watch. How much more work did you do the second time than the first? And so, the block goes 3D. Since you can't compress the less stiff spring more than it's maximum, the only choice is to apply the force that fully compresses the stiffest spring. can you give me some tips on how to start a problem like that. (1) 1.6 m (2) 33 m (3) 0.1 m (4) 16 m (5) 0.4 m Use conservation of mechanical energy before the spring launch and at the graph is K. So using this graph, let's You are always putting force on the spring from both directions. as far at x equals 6D. the spring x0 meters? If the compression is lossless, then the output of the compression is effectively the same data, only recorded in a different number of bytes. direction right now. that's just because this is a linear equation. How do the relative amounts of potential and kinetic energy in this system change over time? In figure 7.10 part C, you can see a graph showing the force applied versus the amount of compression of the spring and the work that this force does is the area underneath this curve. Direct link to Matt's post Spring constant k will va, Posted 3 years ago. How many times can I compress a file before it does not get any smaller? integral calculus right now. restorative force. Did this satellite streak past the Hubble Space Telescope so close that it was out of focus? So, the student is correct that two times, so compressing more, compressing spring more, spring more, will result in more energy when the

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